[blml] New L27 (again)

[Jean-Pierre Rocafort]

Tony Musgrove a écrit :
> At 01:55 AM 3/12/2007, you wrote:
>> Tony Musgrove a écrit :
>>> As I have mentioned previously, I am now using the new
>>> laws and trying to get my spiels right.
>>>
>>> I never had any trouble with the old L27, although some
>>> players were probably excecuted who would now get off
>>> under the new rules.  For example:
>>>
>>> I was playing today as a fill in.  I opened 1NT (strong) and
>>> LHO bid 1C, immediately saying, "Oh, I didn't see you bid",
>>> and replaced the 1C by double before I could say anything.
>>> My partner rejected the 1C insufficient bid, so under the old
>>> rules I would have barred the 1C's partner, since 1C is of the
>>> form:   could be a short as 2.
>>> Upon reflection, I allowed the alteration to double in the case
>>> in question, since their system calls a double of 1NT as "optional".
>>> I suppose that means that it incorporates all the meaning of
>>> 1C (I can open the bidding partner).  I am a bit uneasy about
>>> this ruling since I would not have offered the chance of doubling
>>> had I been called to the table under normal circumstances.
>>>
>>> Still awaiting some definitive ruling on this and other previous
>>> cases
> 
> jpr:
> 
>> i think you were wrong to allow the alteration to double. the condition
>>   for the replacement call to incorporate the information inbedded in
>> the initial bid, means that the set of hands compatible with the
>> replacement call is a subset of the set of hands compatible with the
>> initial call. i think it was not the case here, rather the opposite. for
>> example AK2,Q4,KJ975,J106 may be a double of 1NT and not a 1C opening.
> 
> Indeed, I would be more than happy never to offer the chance to replace a bid
> by a double.  Now I am worried about my 1st case again:
> 
> 1C (1S) 1H.  The offer of a change to 2H would certainly not be a subset
> of hands which could respond 1H to 1C.

i fail to understand what you mean. could you give an example of a hand 
worth of 2H (1C 1S 2H) and not worth of 1H (1C P 1H)?

jpr
> 
> Cheers,
> 
> Tony (Sydney) 
> 
> 
-- 
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