[blml] L53B ("the nad from which declarer led")?

[gesta at tiscali.co.uk]

Grattan Endicott<gesta at tiscali.co.uk
[following address discontinued:
grandeval at vejez.fsnet.co.uk]
*****************************
"Between these shoes soles an' this hat,
Stonds a very respectable mon
An' nob'dy'll contradict that
An' why? Becose nobody con."
      [Samuel Laycock 1692-1763].
+++++++++++++++++++++++++++
----- Original Message ----- 
From: "Peter Eidt" <PeterEidt at t-online.de>
To: "Bridge Laws Mailing List" <blml at amsterdamned.org>
Sent: Monday, March 03, 2008 7:17 AM
Subject: Re: [blml] L53B ("the nad from which declarer led")?


> L53B says:
> ************************************************
> B. Wrong Defender Plays Card to Declarer$B!G(Bs Irregular Lead If
> the defender at the right of the hand from which declarer$B!G(Bs
> lead out of turn was made plays to the irregular lead (but see C), the
> lead stands and Law 57 applies.
> ************************************************
>
> My question involves the meaning of the following phrase:
> "the hand from which declarer$B!G(Bs lead out of turn was made" It
> appears to me that this means either dummy or declarer's own hand, as
> the case may be, but one of my colleagues (who is not a native speaker
> of English9 would like to see if everyone agrees with this (or if
> maybe it applies only to declarer's own hand). Opinions please.

If the lawmakers wanted only leads from declarer's hand
to be included in this law, they would have said so: e.g.
"If declarer's RHO, after a lead out of turn from declarer's hand,
plays to the irregular lead ..."
But they did not say so. The construct "... of the hand from
which declarer's lead out of turn was made ..." is unique.
Declarer made the lead - because he plays both hands -,
but the mere hand from which he does so is arbitrary.

+=+ Correct.  The construction of the language is such that
there are evidently alternative possibilities as to which hand
declarer has led from.
                                        ~ Grattan ~  +=+


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