[blml] new L27
Alain Gottcheiner
agot at ulb.ac.be
Wed Mar 5 17:03:43 CET 2008
richard willey a écrit :
> At this point in the auction, there is some set of hands that John Doe
> could conceivably hold. Let's call this set A
>
> John Doe has just made a 1H bid. The 1H bid defines a set of possible
> hands. Let's call this set B. Furthermore, 1H denies some other set
> of hands. (A 1H overcall is inconsistent with 13 Spades). Let' call
> this set C.
>
> A = The Union of B and C
>
> Here's the catch: The definition of the 1H bid simultaneously
> provides information about both B and C. Suppose that I wanted to
> substitute a 2D call for the insufficient 1H call. 2D shows a subset
> of set B. Lets call this set D.
>
> By my understanding, this wouldn't be legal because the set A – D is
> not a subset of C. (I have access to additional information about the
> set of hands excluded by the 2D call)
>
> The way that I read things, the only way that I can substitute some
> new call is if this new call draws precisely the same boundary as the
> original 1H call. Each and every hand included in set B must be in
> set D. Each and every hand in set C must be in (A – D).
>
> In all honesty, I'd be shocked if anyone can find and example that
> would meet this stringent a test.
>
> I suspect that either
>
> 1. My reading of the Law is incorrect, in which case I'd appreciate it
> if someone picked apart my logic
>
> 2. The new Law 27 is drafted poorly
>
>
AG : not necessarily. Whenever D in a subset of B, non-B (that is, C)
is a subset of non-D, whence no supplementary information from the 1H
bid, whence no damage from the infraction. That's the acid test for
letting it go unpenalized.
Best regards
Alain
More information about the blml
mailing list